Question

PLEASE ANSWER!!!! WILL GIVE 20 POINTS!!!!
The sum of the numerator and the denominator of the certain fraction is equal to 4,140. When the fraction was reduced, the result was 7/13. What was the original fraction?

Answer 1

Original fraction was $\dfrac{7\cdot k}{13\cdot k}$ where $k$ is a reduced common factor. We know that:

$7k+13k=4140\\\\20k=4140\qquad|:20\\\\\boxed{k=207}$

so original fraction:

$\dfrac{7\cdot k}{13\cdot k}=\dfrac{7\cdot 207}{13\cdot 207}=\boxed{\dfrac{1449}{2691}}$

Answer 2

A function assigns the values. The original function is 1449/2691.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given that when the fraction was reduced, the result was 7/13. Therefore, if it is assumed that the fraction was reduced by a. Therefore, we can write the original function as,

(7×a)/(13×a)

Now, since the sum of the numerator and the denominator is 4140. Therefore,

(7×a) + (13×a) = 4140

7a + 13a = 4140

20a = 4140

a = 207

Now, the value of the original function is

(7×a)/(13×a)

= (7×207) / (13×207)

= 1449 / 2691

Hence, the original function is 1449/2691.

Learn more about Function:

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