Respuesta :

x^27x+10=0

Step 1: Factor left side of equation.
(x−2)
(x−5)
=0

Step 2: Set factors equal to 0.
x−2
=0 or x−5
=0

x=2 or x
=5

Answer:   x=2 or x=5
[tex] x^{2} - 7x +10 = 0 [/tex]

The middle term should be factored in such a way that the sum of two numbers is -7x and their product is 10x2. These two factors are -5x and -2x. So re-writing the equation, we get:

[tex] x^{2} - 5x - 2x +10 = 0[/tex]

Taking common, we get:

[tex]x( x - 5) -2 (x-5)=0 \\ \\ (x-5)(x-2)=0[/tex]

This means:
x - 5 = 0
⇒ x = 5

or

x - 2 = 0
⇒ x = 2

Therefore, the solution to the given equation are x = 2 and x = 5