Respuesta :
F = ma
Rearrange this so acceleration is the subject:
A = f/m
Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s
Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s
For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
Rearrange this so acceleration is the subject:
A = f/m
Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s
Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s
For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
Answer:
Part a)
[tex]a = \frac{1}{3} m/s^2[/tex]
Part b)
[tex]a = \frac{5}{9} m/s^2[/tex]
Part c)
[tex]a = \frac{3}{14} m/s^2[/tex]
Explanation:
As per Newton's II law we know that
F = ma
Now we know that
m = 45 kg
F = 15 N
so we will have
[tex]15 = 45 a[/tex]
[tex]a = \frac{15}{45} = \frac{1}{3} m/s^2[/tex]
Now we have
m = 45 kg
F = 25 N
now again from Newton's Law
[tex]25 = 45 a[/tex]
[tex]a = \frac{25}{45} m/s^2[/tex]
[tex]a = \frac{5}{9} m/s^2[/tex]
Now if mass is changed to 70 kg
again we have
[tex]15 = 70 a[/tex]
[tex]a = \frac{15}{70}[/tex]
[tex]a = \frac{3}{14} m/s^2[/tex]