Respuesta :
missing in your question: the molarity of H2SO4 M = 0.1 M
and the equivalence point (mL) = 19.31 mL = 0.019 L
So by using the molarity formula:
molarity of H2SO4 = no of moles of H2SO4 / Volume L
So by substitution:
0.1 M = no of moles of H2SO4 / 0.019 L
∴ no of moles of H2SO4 = 0.1 M * 0.019 L
= 0.0019 mol
and the equivalence point (mL) = 19.31 mL = 0.019 L
So by using the molarity formula:
molarity of H2SO4 = no of moles of H2SO4 / Volume L
So by substitution:
0.1 M = no of moles of H2SO4 / 0.019 L
∴ no of moles of H2SO4 = 0.1 M * 0.019 L
= 0.0019 mol
The moles of H2SO4 can be calculated from the molarity and volume of the acid.
Mole
Moles = mass/molar mass
Also, moles = molarity x volume.
In this case, the titration result would give the volume of acid used. Assuming that the molarity of the acid is known, then the moles of the acid can be calculated as:
Mole = molarity x volume.
If the volume of acid used in the titration is 19.31 mL and the molarity of the acid is 0.1 M:
Mole = 19.31/1000 x 0.1
= 0.001931 mole
More on number of moles can be found here: https://brainly.com/question/12513822