The net chemical equation between Sodium Bicarbonate and H₂SO₄ is the following one:
2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂
To calculate the amount of Sodium Bicarbonate needed to neutralize 1000 L of 0,350 M H₂SO₄ we'll need to use the following conversion factor, to go from the volume of H₂SO₄ to grams of Sodium Bicarbonate:
[tex]1000 L H_2SO_4* \frac{0,350 moles H_2SO_4}{1 L}* \frac{2 moles NaHCO_3}{1 mol H_2SO_4}* \frac{84,007gNaHCO_3}{1molNaHCO_3} \\ \\ =58804,9 g NaHCO_3 [/tex] So, to neutralize 1000 L of 0,350 moles of H₂SO₄ you'll need 58804,9 grams of NaHCO₃
