Respuesta :
From the Avogadro's constant 1 mole = 6.022 × 10^23 atoms
1g of Carbon-12 contains = 1/12 = 0.083 moles
Therefore; 0.083 moles × 6.022×10^23
= 4.9983 × 10^22 atoms
1g of Carbon-13 contains = 1/13 = 0.077 moles
= 4.6370 × 10^22 atoms
Therefore; Carbon-12 has more atoms than Carbon-13
1g of Carbon-12 contains = 1/12 = 0.083 moles
Therefore; 0.083 moles × 6.022×10^23
= 4.9983 × 10^22 atoms
1g of Carbon-13 contains = 1/13 = 0.077 moles
= 4.6370 × 10^22 atoms
Therefore; Carbon-12 has more atoms than Carbon-13
Answer:
Carbon-12
Explanation:
Let's consider Avogadro's number: 1 mole of atoms has 6.02 × 10²³ atoms.
The molar mass of the isotope carbon-12 is 12 g/mol. The atoms contained in 1 g of ¹²C are:
[tex]1g^{12}C.\frac{1mol^{12}C}{12g^{12}C} .\frac{6.02 \times 10^{23}atom ^{12}C}{1mol^{12}C} =5.0 \times 10^{22}atom ^{12}C[/tex]
The molar mass of the isotope carbon-13 is around 13 g/mol. The atoms contained in 1 g of ¹³C are:
[tex]1g^{13}C.\frac{1mol^{13}C}{13g^{13}C} .\frac{6.02 \times 10^{23}atom ^{13}C}{1mol^{13}C} =4.6 \times 10^{22}atom ^{13}C[/tex]
There are more atoms in a 1-g sample of ¹²C than in a 1-g sample of ¹³C.