Question

Solve the compound inequality below:

3−8r ≤ 3+4r or −6+4r < 2+4r


No Solution, Ø


r≤0 or -4>0

r≥0 or -4<0

All Real Numbers

Answer 1

3 - 8r <= 3 + 4r
3 - 3 <= 4r + 8r
0 <= 12r
0 <= r

-6+ 4r < 2+ 4r
4r - 4r < 2 + 6
0 < 8
all real numbers

The "or" statement means combining the sets of solutions.

combined sets = all real numbers