Respuesta :

[tex]5(2x-12)+21=2x+41\\\\5\cdot2x-5\cdot12+21=2x+41\\\\10x-60+21=2x+41\\\\10x-39=2x+41\qquad|+39\\\\10x-39+39=2x+41+39\\\\10x=2x+80\qquad|-2x\\\\10x-2x=2x+80-2x\\\\8x=80\qquad|:8\\\\\boxed{x=10}[/tex]
x= 10.
use LCM to subtract fractions.
start with add/minus
then divide/times
then bracket
Ver imagen OKgoogle