If the width and the length of the rectangle are called x and y, the area is given by:
[tex]A = xy[/tex]
The perimeter of the rectangle is given by:
[tex]P = 2x + y = 20100 feet[/tex]
Combining both equations by eliminating the y variable:
[tex]A = x(20100 - 2x) = 20100x - 2x^2[/tex]
The maximum area can be found by taking the derivative with respect to x and setting it to zero.
[tex] \frac{dA}{dx} = 20100 - 4x = 0[/tex]
Solving for x:
[tex]4x = 20100 \\ x = 5025[/tex]
Solving for y:
[tex]P = 20100 = 2x + y = 2(5025) + y \\ y = 20100 - 10050 \\ y = 10050[/tex]