'parallel to the x-axis'. Parallel lines have the same slope. The x-axis is a horizontal line, and we know that horizontal lines have slopes of 0. Therefore this line must also have a slope of 0. We can plug this and the point into point-slope form to find the equation of the line.
[tex]\sf y-y_1=m(x-x_1)[/tex]
Where 'm' is the slope and (x1, y1) is a point on the line. Plug in what we know:
[tex]\sf y-2=0(x-1)[/tex]
Distribute 0 in the parenthesis, we know that 0 times anything is 0, so the right side of our equation will be equal to 0:
[tex]\sf y-2=0[/tex]
Add 2 to both sides:
[tex]\boxed{\sf y=2}[/tex]
