Given: a trapezoid with b1 and b2 as the length of the bases, h as the length of the altitude, and A as the area. Click on the graphic next to the "h" to choose the correct value based on the given values of b1, b2, and A.
b1 =5 sqrt 2
b2 = 3 sqrt 2
A = 4 sqrt 6
h =

Respuesta :

5 sqrt 7.5 is to the h

Answer:

√3

Step-by-step explanation:

The formula for the area of a trapezoid is

[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]

Plugging in our information, we have

[tex]4\sqrt{6}=\frac{1}{2}(5\sqrt{2}+3\sqrt{2})h[/tex]

Combining like terms in parentheses, we have

[tex]4\sqrt{6}=\frac{1}{2}(8\sqrt{2})h[/tex]

To cancel the 1/2, we will multiply both sides by 2:

[tex]4\sqrt{6}\times 2=\frac{1}{2}(8\sqrt{2})h\times 2\\\\8\sqrt{6}=8\sqrt{2}(h)[/tex]

Divide both sides by 8:

[tex]\frac{8\sqrt{6}}{8}=\frac{8\sqrt{2}(h)}{8}\\\\\sqrt{6}=\sqrt{2}(h)[/tex]

Divide both sides by √2:

[tex]\frac{\sqrt{6}}{\sqrt{2}}=\frac{\sqrt{2}(h)}{\sqrt{2}}\\\\\frac{\sqrt{6}\sqrt{2}}{\sqrt{2}\sqrt{2}}\\\\=\frac{\sqrt{12}}{2}\\\\=\frac{\sqrt{4*3}}{2}\\\\=\frac{2\sqrt{3}}{2}\\\\=\sqrt{3}[/tex]

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