Respuesta :
Answer:
x=5±√414
Explanation:2x2−5x+1=3
aaaaaaa−3a−3aaaSubtract 3 from both sides
2x2−5x−2=0
This equation is not factorable, so use the quadratic formula.
x=−b±√b2−4ac2aaaa foraaaax2+bx+c=0
a=2,b=−5,c=−2
x=−(−5)±√(−5)2−4(2)(−2)2⋅2
x=5±√414
hope this helped :)
alisa202
Answer:
[tex]x=\frac{5\pm\sqrt{41}}{4}[/tex]
Step-by-step explanation:
We have been given an equation [tex]2x^2-5x+1=3[/tex]. We are asked to solve for x.
First of all, we will convert our given equation in standard form of equation as:
[tex]2x^2-5x+1-3=3-3[/tex]
[tex]2x^2-5x-2=0[/tex]
Now, we will use quadratic formula to solve for x.
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}[/tex]
[tex]x=\frac{5\pm\sqrt{25+16}}{4}[/tex]
[tex]x=\frac{5\pm\sqrt{41}}{4}[/tex]
Therefore, the solutions for our given equation are [tex]x=\frac{5\pm\sqrt{41}}{4}[/tex].