a square has one side increased in lenght by two inches and an adjacent side decreaded in length by two inches. If the resulting rectange has an area of 60 square inches, what was the area of the original square?
Let x---------> length original square side x1--------> length resulting rectangle y1--------> wide resulting rectangle A1--------> area resulting rectangle
we know that x1=x+2 y1=x-2 A1=60 in² 60=(x+2)*(x-2)--------> 60=x²-2x+2x-4-------> 60=x²-4------> x²=64 x1=8 x2=-8
the solution is x=8 in the area of the original square is 8*8-------> 64 in²
