Respuesta :
a) the probability would be 0.1014
b) the probability would be 0.4348; no, this would not be unusual
c) the probability would be 0.2319
Explanation
There are 16/24 cans that are regular soda and 8/24 cans that are diet.
a) The probability that the first can is diet would be 8/24. The probability that the second one is diet after the first one was diet would be 7/23. The combined probability would be
8/24(7/23) = 56/552 = 0.1014.
b) The probability that the first can is regular would be 16/24. The probability that the second one is regular would be 15/23. The combined probability would be
16/24(15/23) = 240/552 = 0.4348. Since the probability is nearly half, this would not be considered unusual.
c) The probability that the first can is diet would be 8/24. The probability that the second one is regular after the first can was diet would be 16/23. This probability would be
8/24(16/23) = 128/552 = 0.2319.
If we reversed these, and considered getting a regular can first:
The probability of the first can being regular is 16/24. The probability that the second can is diet after the first one was regular would be 8/23. The probability would be
16/24(8/23) = 128/552 = 0.2319. The probability for c is the same either way.
b) the probability would be 0.4348; no, this would not be unusual
c) the probability would be 0.2319
Explanation
There are 16/24 cans that are regular soda and 8/24 cans that are diet.
a) The probability that the first can is diet would be 8/24. The probability that the second one is diet after the first one was diet would be 7/23. The combined probability would be
8/24(7/23) = 56/552 = 0.1014.
b) The probability that the first can is regular would be 16/24. The probability that the second one is regular would be 15/23. The combined probability would be
16/24(15/23) = 240/552 = 0.4348. Since the probability is nearly half, this would not be considered unusual.
c) The probability that the first can is diet would be 8/24. The probability that the second one is regular after the first can was diet would be 16/23. This probability would be
8/24(16/23) = 128/552 = 0.2319.
If we reversed these, and considered getting a regular can first:
The probability of the first can being regular is 16/24. The probability that the second can is diet after the first one was regular would be 8/23. The probability would be
16/24(8/23) = 128/552 = 0.2319. The probability for c is the same either way.
Answer:
Part C. you do 1- ((8/24)(7/23)+(16/24)(15/23)=.4638
Step-by-step explanation: