Question

Suraj took a slice of pizza from the freezer and put it in the oven. The pizza was heated at a constant rate.
The table compares the pizza's temperature (in degrees Celsius) and the time since Suraj started heating it (in minutes).

Time(Minutes) Temperature(degree celsius)
1                             2.5
7                             47.5
13                           92.5

How long did it take the pizza to reach 100 degrees Celsius

Answer 1

For this case, the first thing we should do is write the linear function that best suits the table.
 In this case we have the following function:
 y = 7.5x - 5
 C = 7.5t-5
 For C = 100 we have:
 100 = 7.5t-5
 We clear the time:
 t = (100 + 5) / (7.5)
 t = 14
 Answer:
 it did take the pizza to reach 100 degrees Celsius about 14 minutes.

Answer 2

Since the pizza was heated at a constant rate, the table describes a linear relationship.

Moreover, the rate of change of this relationship corresponds to the rate at which the pizza was heated.

The table of values shows that for each increase 6, minutes in time, temp increased by 45 degrees Celsius. The rate at which the pizza was heated is the ratio of those corresponding differences

In conclusion, the pizza was heated at a rate of 7.5 degrees Celsius per minute.