Question

Identify the spectator ion in this reaction. highlight your answer. ba(oh)2(aq) + h2so4(aq) → baso4(s) + h2o(l) ba2+ so42- oh- h+ there is no spectator ion.

Answer 1

Answer is: there is no spectator ion.
Balanced reaction hemical reaction:
Ba(OH)₂(aq) + H₂SO₄(aq) → BaSO₄(s) + 2H₂O(l).
Net ionic reaction:
Ba²⁺(aq) + 2OH⁻(aq) + 2H⁺(aq) + SO₄²⁻(aq) → BaSO₄(s) + 2H₂O(l).
Barium cation and sulfate anion form precipate and hydrogen cations and hydroxide anion form molecular water. A spectator ion is an ion that exists as a reactant and a product in a chemical equation

Answer 2

Answer: The correct answer is no spectator ion.

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sulfuric acid and barium hydroxide is given as:

$H_2SO_4(aq.)+Ba(OH)_2(aq.)\rightarrow BaSO_4(s)+2H_2O(l)$

Ionic form of the above equation follows:

$2H^+(aq.)+SO_4^{2-}(aq.)+Ba^{2+}(aq.)+2OH^-(aq.)\rightarrow BaSO_4(s)+2H_2O(l)$

There are no spectator ions in the equation. So, the above reaction is the net ionic equation.

Hence, the correct answer is no spectator ion.