nitrogen + hydrogen = ammonia
N2 + 3 H2 ---> 2 NH3
from ideal gas equation that is pv =nRT where p is pressure, v= volume, n= number of moles,R = gas constant and t= temperature
from information above in the question
P= 49.6 kpa
V=22.7 L
t =93 +273=366 K
R=8.314 l.Kpa /mol
n=?
from ideal gas equation n= Pv/RT
n= (49.6 x22.7) /( 8.314 x 366) = 0.37 moles of nitrogen
by use of moles ratio between N2 to NH3 from equation above which is 3:2 therefore moles of NH3 = 0.37 x2/3= 0.247 moles of Nh3
1mole of ideal gas = 22.4 L at stp
what about 0.247 moles
( 0.247 x22.4)/ 1= 5.53 liters of ammonia
