Respuesta :
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is [tex]25in^{2}[/tex], and its volume is [tex]250in^{3}[/tex]. We also know that the area of the larger figure is [tex]36in^{2}[/tex]; since we don't now its volume, lets represent it with [tex]X[/tex]:
[tex] \frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} [/tex]
[tex] \frac{25}{36} = \frac{250}{X} [/tex]
[tex]X= \frac{(250)(36)}{25} [/tex]
[tex]X=360[/tex]
We can conclude that the volume of the larger figure is [tex]360in^{3}[/tex]; therefore, the correct answer is a.
We know that the area of the smaller figure is [tex]25in^{2}[/tex], and its volume is [tex]250in^{3}[/tex]. We also know that the area of the larger figure is [tex]36in^{2}[/tex]; since we don't now its volume, lets represent it with [tex]X[/tex]:
[tex] \frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} [/tex]
[tex] \frac{25}{36} = \frac{250}{X} [/tex]
[tex]X= \frac{(250)(36)}{25} [/tex]
[tex]X=360[/tex]
We can conclude that the volume of the larger figure is [tex]360in^{3}[/tex]; therefore, the correct answer is a.