Question

An electron is located in an electric field of magnitude 600. newtons per coulomb. what is the magnitude of the electrostatic force acting on the electron?

Answer 1

The magnitude of the electrostatic force acting on a charge q is the product between the charge and the intensity of the electric field E. The magnitude of the electron charge is $q=1.6 \cdot 10^{-19}C$ (we are not interested in the sign), so the electrostatic force magnitude is
$F=qE=(1.6 \cdot 10^{-19}C)(600 N/C)=9.6\cdot 10^{-17}N$

Answer 2

The magnitude of the electrostatic force acting on the electron is 9.6 x 10⁻¹⁷ N.

The given parameters:

• Electric field of the electron, E = 600 N/C
• Charge of an electron, q = 1.6 x 10⁻¹⁹ C

The magnitude of the electrostatic force acting on the electron is calculated as follows;

F = Eq

F = 600 x 1.6 x 10⁻¹⁹

F = 9.6 x 10⁻¹⁷ N.

Thus, the magnitude of the electrostatic force acting on the electron is 9.6 x 10⁻¹⁷ N.

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