Question

Find any points of discontinuity for the rational function y=(x-8)/(x^2 +5x-6)

Answer 1

A point of discontinuity is any point that yields an undefined answer when plugged in (meaning there’s division by zero involved).

By that, we can find the points of discontinuity by setting the denominator equal to 0.

x^2 + 5x - 6 = 0

(x + 6)(x - 1) = 0

x = 1, -6

Those are your points of discontinuity

Answer 2

x = -5, x = 1 are the points of discontinuity for the rational function.

What is discontinuity function ?

discontinuous function is the opposite. It is a function that is not a continuous curve, meaning that it has points that are isolated from each other on a graph. When you put your pencil down to draw a discontinuous function, you must lift your pencil up at least one point before it is complete.

If you ever see a function with a break of any kind in it, then you know that function is discontinuous. In the function we have here, you can see how the function keeps going with a break.

According to the question,

y = x-8/ $x^{2}$+4x-5

y = x-8/ $x^{2}$+4x-5 find any points of discontinuity for the rational function When denominator becomes 0 in a rational function then there will be a break in the graph To find any points of discontinuity for the rational function

we set the denominator =0

solve for

$x^{2}$ + 4x -5 =0

$x^{2}$ + 5x - 1x -5 = 0

x ( x + 5 ) - 1 ( x + 5 ) = 0

( x + 5 ) ( x - 1 ) = 0

x + 5 = 0 , x - 1 = 0

x = -5 , x = 1

Now we factor $x^{2}$ +4x -5 product is -5 , 1

Hence, x = -5, x = 1 are the points of discontinuity for the rational function

To learn more about discontinuity from here

https://brainly.com/question/2750981

#SPJ2