Question

find the cordinates of the midpoint 1,3 and 7,-1

Answer 1

(1,3) and (7,-1)

$(\frac{1+7}{2}, \frac{3+(-1)}{2})\\\\(\frac{8}{2}, \frac{2}{2})\\\\\boxed{\bf{(4,1)}}$

The midpoint of (1,3) and (7,-1) is (4,1).