Question

WILL GIVE A BRAINLEST!!!!!!!!!!

Which is true about the statements

The graph of f(x) has a vertex of (–4, 6).
The graph of f(x) is horizontally stretched.
The graph of f(x) opens upward.
The graph of f(x) has a domain of x <=–6.

Answer 1

the second option


hope this helps<3

Answer 2

Answer: B) The graph of f(x) is horizontally stretched.

Step-by-step explanation: We are given an absolute function $f(x)=-\frac{2}{3} |x+4|-6$.

The standard equation of an absolute function is $f(x)= a|x-h|+k$.

Where (h,k) is the vertex of the absolute function.

If we compare $f(x)=-\frac{2}{3} |x+4|-6$ and $f(x)= a|x-h|+k$, we can see a=$-\frac{2}{3}$, h= -4 and h= -6.

Therefore, vertex of the given function is (-4,-6).

Because we have value of a is a negative number so it would open down.

An absolute function always have domain " All real numbers".

Therefore, first, third and fourth options are incorrect.

So, the second option would only be applicable.

B) The graph of f(x) is horizontally stretched.