Respuesta :
Length of the rectangular tabletop = 4 3/4 feet
= 19/4 feet
Let us assume the width of the rectangular table = x feet
Area of the rectangular tabletop = 11 7/8 square feet
= 95/8 square feet
Then
Area = length * width
95/8 = 19x/4
19x * 8 = 95 * 4
x = (95 * 4)/(19 * 8)
= 5/2 feet
= 2 1/2 feet
So the width of the rectangular tabletop is 2 1/2 feet. i hope the procedure for finding the solution is easy enough for you to understand.
= 19/4 feet
Let us assume the width of the rectangular table = x feet
Area of the rectangular tabletop = 11 7/8 square feet
= 95/8 square feet
Then
Area = length * width
95/8 = 19x/4
19x * 8 = 95 * 4
x = (95 * 4)/(19 * 8)
= 5/2 feet
= 2 1/2 feet
So the width of the rectangular tabletop is 2 1/2 feet. i hope the procedure for finding the solution is easy enough for you to understand.
area=legnth times width
area=11 and 7/8
legnth=4 and 3/4
width=x
covvert to impropert fractions
11 and 7/8=88/8+7/8=95/8
4 and 3/4=16/4+3/4=19/4
95/8=19/4 times x
multiply boths ides by the inverse of 19/4 to make it one (multiply both sides by 4/19)
380/152=2 and 1/2
width=2 and 1/2 feet
area=11 and 7/8
legnth=4 and 3/4
width=x
covvert to impropert fractions
11 and 7/8=88/8+7/8=95/8
4 and 3/4=16/4+3/4=19/4
95/8=19/4 times x
multiply boths ides by the inverse of 19/4 to make it one (multiply both sides by 4/19)
380/152=2 and 1/2
width=2 and 1/2 feet