Question

a basketball of mass 0.23 kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a velocity of 15m/s a)calculate the impulse of the force of the wall on the basketball show your work?

Answer 1

     Using the Definition of Impulse, we have:

$\Delta I=\Delta Q \\ \Delta I=m(v-v_{\circ}) \\ \Delta I=0.23(15-20) \\ \boxed {\Delta I=1.15~Ns}$

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