For a carnival game, containers are arranged in a triangular display. The top row has 1 container. The second row has 2 container. the third row has 3 containers. The pattern continues until the bottom row, which has 10 containers. A contestant knocks down 29 containers on the first throw. How many containers remain?

For this, you will need to know the triangle numbers. To know how many are on row ten, find the cumulative frequency (running total) of every number up to ten

1 = 1
2 = 3
3 = 6
4 = 10
5 = 15
6 = 21
7 = 28
8 = 36
9 = 45
10 = 55

If there are 55 containers and 29 are knocked down, we do
55 - 29 = 26
26 containers remain

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ap8997154 ap8997154 · Answer 2 · 2022-08-04T09:13:18+02:00

The addition is one of the four fundamental mathematical operations. The number of containers that are remaining is 26.

What is Addition?

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

Given that for a carnival game, containers are arranged in a triangular display. The top row has 1 container. The second row has 2 containers. the third row has 3 containers. The pattern continues until the bottom row, which has 10 containers.

Thus, the total number of containers in the ten rows is,

S = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55

Now, A contestant knocks down 29 containers on the first throw. Therefore, the number of containers that are remaining are,

Number of containers remaining

= Total number of containers - Number of containers that contestant knocks

= 55 - 29

= 26

Hence, the number of containers that are remaining is 26.

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