Question

Length of a rectangle is 4 inches less than twice it’s width of the perimeter is 70 inches what’s the dimensions?

Answer 1

W= width
L= length= 2W-4
Perimeter= 70

FIND WIDTH:
P= 2(L + W)
P= 2L + 2W
substitute 2W-4 for L
70= 2(2W-4) + 2W
multiply 2 by all in parentheses
70= (2*2W) + (2*-4) + 2W
70= 4W - 8 + 2W
combine like terms
70= 6W - 8
add 8 to both sides
78= 6W
divide both sides by 6
13= W

FIND LENGTH:
substitute w=13 to find width
L= 2W-4
L= 2(13)-4
L= 26-4
L= 22

CHECK:
P= 2(L + W)
70= 2(22 + 13)
70= (2*22) + 2(13)
70= 44 + 26
70= 70

ANSWER:
length= 22 inches
width= 13 inches

Hope this helps! :)