The wavelength in water will be 4.4 times the wavelength in air.
The distance between two adjacent corresponding points of the same phase on the wave, such two adjacent crests, troughs, or zero crossings is known as the wavelength.
The wavelength of the sound wave in water is given as;
[tex]\rm v= f \lambda \\\\ \lambda= \frac{v}{f} \\\\ \lambda= \frac{1500}{100} \\\\ \lambda_w=15[/tex] nm
The wavelength of the sound wave in air is given as;
[tex]\rm v= f \lambda \\\\ \lambda= \frac{v}{f} \\\\ \lambda= \frac{340}{100} \\\\ \lambda_A=3.4 nm[/tex]
The ratio between the wavelength is found as;
[tex]\rm R=\frac{\lambda_w}{\lambda_A} \\\\ \rm R=\frac{15}{3.4}\\\\ \rm R=4.4[/tex]
Hence the wavelength in water will be 4.4 times the wavelength in air.
To learn more about the wavelength refer to the link;
https://brainly.com/question/7143261