What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare
100.0 milliliters of a 0.50 M acetic acid solution?

Use the equation

Mconcentrated × Vconcentrated = Mdilute × Vdilute.

90points given to correct answer

Respuesta :

 

Answer is: volume is 20 mL.
c
₁(CH₃COOH) = 2,5 M.
c
₂(CH₃COOH) = 0,5 M.
V
₂(CH₃COOH) = 100 mL.
V
₁(CH₃COOH) = ?
c
₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).
2,5 M · V
₁(CH₃COOH) = 0,5 M · 100 mL.
V
₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.
V
₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.

Answer:

20 milliliters

Explanation:

I don't cap

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