Question

Luke and Christopher go to the movie theater and purchase refreshments for their friends.

Luke spends a total of $41.00 on 3 drinks and 10 bags of popcorn.

Christopher spends a total of $11.00 on 2 drinks and 2 bags of popcorn.

Write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn.

Using these equations, determine and state the price of a bag of popcorn, to the nearest cent.

Answer 1

let x= $ of drinks
let y= $ of popcorn 
so the first equation would be:      (3x+10y=41)2
so the second equation would be: (2x+ 2y=11)-3
so now use the process of elimination:
6x+20y=82                                                
-6x-6y=-33   the x's cancel out

14y=49
/14  /14
y=3.5

now plug y back into one of the equations above to find out x:
6x+20(3.5)=82
6x+70=82
6x=12
x=2 
a bag of popcorn is $3.50
a drink is $2



Hope this helped you!! :)