Question

WILL GIVE A BRAINLEST!!!!!!

Solve and check : c-4/c-2=c-2/c+2 - 1/2-c


The solution is c =

How many extraneous solutions are there?

Answer 1

Answer:

C=14 and the second answer is ZERO

Step-by-step explanation:

Answer 2

$c=14$

There is no extraneous solution because as we put the value of c in equation (1), it does not make the equation (1) not define.

Step-by-step explanation:

Given :

$\dfrac {c-4}{c-2} = \dfrac {c-2}{c+2} - \dfrac{1}{2-c}$                   --------- (1)

Calculation :

$\dfrac {c-4}{c-2} = \dfrac {(c-2)^2+(c+2)}{(c+2)(c-2)}$

$c-4 = \dfrac {(c^2-4c+4)+(c+2)}{(c+2)}$

$(c-4)(c+2) = (c^2-3c+6)$

$(c^2-2c-8) = (c^2-3c+6)$

$c=14$

There is no extraneous solution because as we put the value of c in equation (1), it does not make the equation (1) not define.

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https://brainly.com/question/11897796?referrer=searchResults