What are the values of a and b?
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Answer:
[tex]A= \frac{400}{21} B=\frac{580}{21}[/tex]
Step-by-step explanation:
You just have to remember the rules of the triangles in order to be able to solve this:
The rule of trigonometry that you will have to use is a is similie to 20, B is simile to 29 and 20 is 20.
So you would have to put them like this:
[tex]\frac{21}{20}= \frac{20}{a}= \frac{29}{b}[/tex]
You just have to clear the equations for A and B:
[tex]a=\frac{20*20}{21}=\frac{400}{21}\\ b=\frac{29*20}{21} =\frac{580}{21}[/tex]
So that would be your answer.
The value of 'a' is 400/21 and the value of 'b' is 580/21 and this can be determined by using the properties of trigonometry.
According to the properties of trigonometry:
[tex]\dfrac{21}{20}=\dfrac{20}{a}=\dfrac{29}{b}[/tex] --- (1)
Now, in order to determine the value of 'a' use the above equation:
[tex]\dfrac{21}{20}=\dfrac{20}{a}[/tex]
Cross multiply in the above equation.
[tex]21a = 20\times 20[/tex]
21a = 400
Divide 400 by 21 in order to get the value of a.
[tex]a = \dfrac{400}{21}[/tex]
Now, to determine the value of 'b' again use the equation (1).
[tex]\dfrac{20}{\dfrac{400}{21}}=\dfrac{29}{b}[/tex]
Cross multiply in the above expression.
[tex]20b = 29\times \dfrac{400}{21}[/tex]
[tex]20b = \dfrac{11600}{21}[/tex]
Now, divide on both sides by 20 in the above expression.
[tex]\rm b = \dfrac{11600}{21\times 20}[/tex]
[tex]\rm b = \dfrac{580}{21}[/tex]
For more information, refer to the link given below:
https://brainly.com/question/19237987