Respuesta :
For this case we have an equation of the form:
[tex]y = A * (b) ^ x [/tex]
Where,
A: initial price
b: rate of change
x: time
When 0 <b <1, then the function decreases.
For this case we have the following function:
[tex]y = 22000 (.88) ^ (x + 2) [/tex]
Where,
[tex]b = 0.88 [/tex]
We observe that the function decreases.
The percentage of decrease is given by:
[tex](1-0.88) * 100 = 12 [/tex]
Answer:
C.The price of the boat decreases by 12% every year.
[tex]y = A * (b) ^ x [/tex]
Where,
A: initial price
b: rate of change
x: time
When 0 <b <1, then the function decreases.
For this case we have the following function:
[tex]y = 22000 (.88) ^ (x + 2) [/tex]
Where,
[tex]b = 0.88 [/tex]
We observe that the function decreases.
The percentage of decrease is given by:
[tex](1-0.88) * 100 = 12 [/tex]
Answer:
C.The price of the boat decreases by 12% every year.
The formula for the growth rate is given by
[tex] y=a(b)^x [/tex]
Now when b is greater than 1 , then it is increasing function
and when b is less than 1 , then it is decreasing function.
Now in the function
[tex] 22000(.88)^{(x+2)} [/tex]
here value of b is 0.88 , which is less than 1 , so it is decreasing function
And decay rate is given by
1-r = 0.88
Subtract 1 from both sides
-r = 0.88-1
-r = -0.12
r = 0.12
or r= 12%
It means it is decreasing at a rate of 12%
Hence Option C is correct
C.The price of the boat decreases by 12% every year.