The figure is formed of a rectangle and a triangle
The rectangle has dimensions:length=38ft and width=20ft
The triangle has dimensions:base=33ft and height=9ft
Area of rectangle=length*width of rectangle
Area of triangle=[tex] \frac{1}{2} [/tex]*base*height
Area of figure= area of rectangle + area of triangle
Area=length*width+[tex] \frac{1}{2} [/tex]*base*height
Area=38*20 + [tex] \frac{1}{2} [/tex]*33*9
Area=760+[tex] \frac{1}{2} [/tex]*297
So we have, Area=760+[tex] \frac{297}{2} [/tex]
Or, Area=760+148.5
Area=908.5
Area of the floor=908.5[tex] ft^{2} [/tex]
