Respuesta :
A: the formula would be f(x) = P(R) ^T or f(x) = Principle(rate)^time
B: f(x) = 20,000(0.85)^5
C: = 8,874.10625
D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time.
E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.
B: f(x) = 20,000(0.85)^5
C: = 8,874.10625
D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time.
E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.
AnswerA: the formula would be f(x) = P(R) ^T or f(x) = Principle(rate)^time
B: f(x) = 20,000(0.85)^5
C: = 8,874.10625
D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time.
E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.
Step-by-step explanation:A: the formula would be f(x) = P(R) ^T or f(x) = Principle(rate)^time
B: f(x) = 20,000(0.85)^5
C: = 8,874.10625
D: Yes, the final answer makes sense compared to the origional cost of the car in relation to the formula. As well, time decreases the value of a car, so for the cost to be so low only makes sense due to the cars decrease in value or an extended and elongated amount of time.
E: You can solve this equation graphically by plotting th point at 20,000 and then taking 85% of 20,000 and plotting it each time until you get to the fifth year.