Question

A given line has the equation 10x+2y=-2. What is the equation , in slope intercept form, of the line that is parallel to the given line that passes through the point (0,12)

Answer 1

2y = - 10x - 2
y = - 10x / 2 - 2/2
y = - 5x - 1

The new line is y = -5x + b
Use (0,12) to get b
12 = -5(0) + b
b = 12
y = - 5x + 12 <<<<<<===== Answer 

Answer 2

Answer:

y = -5x + 12

Step-by-step explanation:

Slope intercept form of a line is,

y = mx + c

Where, m is the slope of the line,

Here, the given equation of line,

10x+2y=-2,

2y = - 10x - 2

y = -5x - 1,

By comparing,

m = -5,

So, the slope of line 10x+2y=-2 is -5,

We know that the two parallel line have same slope,

Let the equation of the parallel line of the 10x+2y=-2  is,

y = -5x + c

According to the question,

It passes through the point (0,12),

That is (0, 12) must satisfy this line,

12 = -5(0) + c ⇒ c = 12,

Hence, the equation of the parallel line is,

y = -5x + 12