Chebyshev's inequality:
For a wide class of distributions, no more than [tex]\frac{1}{k^2}[/tex] of the values can be outside of k standard deviations of the mean.
Here,
n = 16
μ = 2
σ = 1
range iin question = 0 to 4 [tex]=2\pm2=\mu\pm\sigma[/tex]
=> k=2
[tex]\frac{1}{k^2}=\frac{1}{4}[/tex]
meaning that at most 1/4 of the sample is outside the given range, or 3/4 of the sample= (3/4)*16 =12 is within the given range of 0 to 4 televisions.
Answer: at least 12 out of 16 households have between 0 to 4 televisions, according to the Chebyshev's inequality.