Question

A classic counting problem is to determine the number of different ways that the letters of "embarrass""embarrass" can be arranged. find that number

Answer 1

Total number of letters in word "embarrass" = 9
Following letters are repeated:
Letter a occurs 2 times
Letter r occurs 2 times
Letter s occurs 2 times

The number of different ways the letters of word embarrass can be arranged can be calculated using permutations. The total number of different ways the letters of "embarrass" can be arranged will be:

$\frac{9!}{2!*2!*2!}=45360$

Thus there are 45360 different ways to arrange the letters of the word embarrass. 

Answer 2

The number of different ways that the letters of "EMBARASS" can be written is $45360$.

The given word is "EMBARRASS".

Total number of words is $9$.

Total number of letter 'A" is $2$.

Total Number of letter "R" is $2$

Total Number of letter "S" is $2$

So, the total of different ways of rearranging the letters from the word "EMBARASS" is

$\dfrac{9!}{2!\times 2!\times 2!}=45360$

Hence, the number of different ways that the letters of "EMBARASS" can be written is $45360$.

Learn more about combinations here:

https://brainly.com/question/8018593?referrer=searchResults