Using this equation:
E(U) = E(Fe) kq / r² = k2q / (R-r)² 1/r² = 2/(R-r)²
(R-r)² = 2r²
R² - 2Rr + r² = 2r²
r² + 2Rr - R² = 0 is a quadratic equation to solve
r² + 84.6r - 1789 = 0 ► solving for the quadratic equation
r² x 10 + 84.6r x 10 - 1789 x 10 = 0 x 10
refining: 10r² + 846r - 17890 = 0
so a = 10, b = 846, and c = -17890
r = -846 + √846² - 4 x 10 (-17890) / 2 x 10
r = 17.52 nm