Respuesta :
the original price of the car would be $17,040 brand new
hope this helps
hope this helps
Answer:
[tex] A(6) = 12000 = A_o e^{-0.07 *6}[/tex]
And solving for the initial amount [tex] A_o[/tex] we got:
[tex] A_o = \frac{12000}{e^{-0.07*6}}= 18263.539[/tex]
So then the original price for the car would be approximately 18263.539$
Step-by-step explanation:
For this case we can use the exponential model given by:
[tex] A(t) = A_o e^{bt}[/tex]
Where:
[tex]A_o[/tex] represent the initial amount for the car
[tex]b=-0.07[/tex] represent the exponential growth/decay rate
t represent the number of years. With t =0 at the begin
After 6 year we have that t =6, and we know this condition:
[tex] A(6) = 12000[/tex]
So then we can use the exponential model formula and the condition given and we have this:
[tex] A(6) = 12000 = A_o e^{-0.07 *6}[/tex]
And solving for the initial amount [tex] A_o[/tex] we got:
[tex] A_o = \frac{12000}{e^{-0.07*6}}= 18263.539[/tex]
So then the original price for the car would be approximately 18263.539$