Question

Find the distance between the two points. Round to the nearest tenth if necessary. (10, –4), (5, 8)
169

7

13

16

Answer 1

$d= \sqrt{(10-5)^2+(-4-8)^2}= \sqrt{25+144}= \sqrt{169}=13$

Answer 2

Answer: 13

If you ask this question may be you do not know the formula of the distance between two points or you do not know how to use it, so I am going to explain you both.

1) Formula of the distance betweer two points:

Say the point A has coordinates (x1, y1) and the point B has coordinates (x2, y2), the distance, d, between the points A and B is given by the formula:

$d^2= (x_1-x_2)^2+(y_1+y_2)^2} = d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

2) So, to apply that formula you need the coordinates of the two points.

In this case the coordinates of the point (10,-4) are: x = 10, y = -4

The coordinates of the point (5,8) are: x = 5, y = 8.

3) This is the application:

$d= \sqrt{(10-5)^2+(-4-8)^2}= \sqrt{(5)^2+(-12)^2}= \sqrt{25+144} d= \sqrt{169}=13$

So, the answer is 13.