Respuesta :
the complete question in the attached figure
we have
$72 ------------------------------------ > for every television sold
$90 ------------------------------------ > for every computer sold.
let
x--------------------- > numbers of television sold
y--------------------- > numbers of computer sold
then
72x+90y >= $360 ----------- >72x/72+90y/72 >= $360 /72---- >x+1.25y >= $5
y >= (5-x)/1.25--------------see the graph in attached figure
case A---------- > (5,2) (3,3) (1,4)
72x+90y --------- > 72*5+90*2=540 >= 360----- > is solution
72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution
72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution
case B------------ > (4,0) (2,2) (1,1)
72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution
72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution
72x+90y --------- > 72*1+90*1=162 < 360----- > is not solution
case C------------ > (3,1) (2,2) (1,0)
72x+90y --------- > 72*3+90*1=306 < 360----- > is not solution
72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution
72x+90y --------- > 72*1+90*0=72 < 360----- > is not solution
case D------------ > (4,0) (3,3) (1,4)
72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution
72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution
72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution
the answer is case A
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Answer: A. (5, 2), (3, 3), and (1, 4) are three possible solutions.
Explanation:
This is the set of answer choices for this problem:
A. (5, 2), (3, 3), and (1, 4) are three possible solutions.
B. (4, 0), (2, 2), and (1, 1) are three possible solutions.
C. (3, 1), (2, 2), and (1, 0) are three possible solutions. .
D. (4, 0), (3, 3), and (1, 4) are three possible solutions.
This is how you solve it.
1) name the variables:
t: number of tv sold
c: number of computer sold
2) model the profit = 72t + 90c
3) set the inequality:
The manager's target is to make at least $360 => profit ≥ 360
=> 72t + 90c ≥ 360
simplify dividing by 9 => 8t + 10c ≥ 40
simplify dividing by 2 => 4t + 5c ≥ 20
4) graph 4t + 5x ≥ 20
- draw the line 4t + 5c = 20
notice that 5c = - 4t + 20 => c = (-4/5)t + 4
=> slope -4/5, c intercept 4
So, the solution is the region above the line 4t + 5c = 20, in the first quatrant ( t≥0, and c≥0)
5) use the set of answer choices to probe which are solutions:
A. (5, 2), (3, 3), and (1, 4) are three possible solutions.
Use the inequality to probe each pair:
- point (5,2): 4(5) + 5(2) = 20 + 10 = 30 ≥ 36 => ok
- point (3,3): 4(3) + 5(3) = 12 + 15 = 27 ≥ 36 => ok
- point (1,4): 4(1) + 5(4) = 4 + 20 = 24 ≥ 20 => ok
Therefore that is the answer.
Check how the other choices are discarded.
B. (4, 0), (2, 2), and (1, 1) are three possible solutions.
- point (1,1) is not solution: 4(1) + 5(1) = 4 + 5 = 9 which is not ≥ 20 => not solution.
C. (3, 1), (2, 2), and (1, 0) are three possible solutions. .
- point (1,0) is not solution: 4(1) + 5(0) = 4 + 0 = 4 which is not ≥ 20 => not solution.
D. (4, 0), (3, 3), and (1, 4) are three possible solutions.
- point (4,0) is not solution: 4(4) + 5(0) = 16 + 0 = 16 which is not ≥ 20.
Explanation:
This is the set of answer choices for this problem:
A. (5, 2), (3, 3), and (1, 4) are three possible solutions.
B. (4, 0), (2, 2), and (1, 1) are three possible solutions.
C. (3, 1), (2, 2), and (1, 0) are three possible solutions. .
D. (4, 0), (3, 3), and (1, 4) are three possible solutions.
This is how you solve it.
1) name the variables:
t: number of tv sold
c: number of computer sold
2) model the profit = 72t + 90c
3) set the inequality:
The manager's target is to make at least $360 => profit ≥ 360
=> 72t + 90c ≥ 360
simplify dividing by 9 => 8t + 10c ≥ 40
simplify dividing by 2 => 4t + 5c ≥ 20
4) graph 4t + 5x ≥ 20
- draw the line 4t + 5c = 20
notice that 5c = - 4t + 20 => c = (-4/5)t + 4
=> slope -4/5, c intercept 4
So, the solution is the region above the line 4t + 5c = 20, in the first quatrant ( t≥0, and c≥0)
5) use the set of answer choices to probe which are solutions:
A. (5, 2), (3, 3), and (1, 4) are three possible solutions.
Use the inequality to probe each pair:
- point (5,2): 4(5) + 5(2) = 20 + 10 = 30 ≥ 36 => ok
- point (3,3): 4(3) + 5(3) = 12 + 15 = 27 ≥ 36 => ok
- point (1,4): 4(1) + 5(4) = 4 + 20 = 24 ≥ 20 => ok
Therefore that is the answer.
Check how the other choices are discarded.
B. (4, 0), (2, 2), and (1, 1) are three possible solutions.
- point (1,1) is not solution: 4(1) + 5(1) = 4 + 5 = 9 which is not ≥ 20 => not solution.
C. (3, 1), (2, 2), and (1, 0) are three possible solutions. .
- point (1,0) is not solution: 4(1) + 5(0) = 4 + 0 = 4 which is not ≥ 20 => not solution.
D. (4, 0), (3, 3), and (1, 4) are three possible solutions.
- point (4,0) is not solution: 4(4) + 5(0) = 16 + 0 = 16 which is not ≥ 20.