Question

Will mark as Brainliest.

Solve using the Quadratic Formula.
x^2 + 3x - 5 = 0

A) x = 3 ± $\sqrt29$ / 2

B) x = 3 ±$\sqrt14$ / 2

C) x = 3 ± $\sqrt29$ / 3

D) x = -3 ±$\sqrt14$ / 2

Answer 1

$x^2 + 3x - 5 = 0\\\\x= \frac{-3б \sqrt{3^2-4\cdot1\cdot(-5)} }{2}\\\\ x= \frac{-3б \sqrt{9+20} }{2}\\\\ x= \frac{-3б \sqrt{29} }{2}$