Talia would need 15 strawberries and 6 oranges. This is solved by cross multiplication.
(S)trawberries explanation:
[tex] \frac{10}{8} * \frac{S}{12} [/tex] S will be what is multiplied by 8 which will get us the same product of 10 * 12, which is 120. S will be our answer for the strawberries.
S' solution: S = [tex] \frac{10 * 12}{8}[/tex] → S =[tex] \frac{120}{8} [/tex] S = 15
Therefore S is 15.
(O)ranges explanation:
[tex] \frac{4}{8} * \frac{O}{12} [/tex] Same thing applies, but this time we need the number O equals when multiplied by 8, will get us the product of 12 * 4, which is 48.
O's solution: O = [tex] \frac{4 * 12}{8} [/tex] O = [tex] \frac{48}{8}[/tex] O = 6
Therefore O is 6.
