Question

What might you expect to observe from this double-displacement reaction?
2NaOH(aq) + MgCl2(aq) -> 2NaCl + Mg(OH)2

A. NaCl precipitate will be formed
B. Mg(OH)2 precipitate will be formed
C. One of these products will bubble out as a gas

Answer 1

B. Mg(OH)2 precipitate will be formed

Answer 2

The chemical reaction in which one component of each reactant molecules gets exchanged to form products are known as a double-displacement reaction.

The given double-displacement reaction with there respective phases is:

$2NaOH(aq)+MgCl_2(aq)\rightarrow Mg(OH)_2(s)+2NaCl(aq)$

Precipitation of $Mg(OH)_2$ takes place and the $NaCl$ will remain in the solution in aqueous phase.

Thus, option b is correct.