The z-score is given by:
[tex]z = \dfrac{x-\mu}{\sigma}[/tex]
where z is the z-score, x is the value whose z-score we want to calculate, μ is the mean, and σ is the standard deviation.
Hence, in your example:
[tex]z = \dfrac{680-518}{114} =1.42[/tex]
The z-score of a value is the number of standard-deviations the value is above the mean. In this case, Ezra's score is 1.42 standard-deviations above the mean.
This standardized value allows you to answer questions like: "Is Ezra's score a high score?" Well, it's obviously above the mean (162 points above the mean). But, is that a high difference? With the z-score you know that it is 1.42 standard-deviations above the mean. In a normal distribution, only 16% of the values are 1 standard deviation or more above the mean, and only 2.3% are above 2 standard deviations or more above the mean. Hence, Ezra's is a high score (between the 16% and the 2.3% best scores).