Respuesta :
Answer: the restrictions on the domain of (u°v) (x) are x ≠ 2 and which v(x) ≠ 0.
Justification:
1) the function (u ° v) (x) is u [ v(x) ], this is, you have to apply first the function v(x) whose argument is (x), and later the function u (v(x) ) whose argument is v(x).
2) So, the domain of the composed function (u ° v) (x) has to take into account the values for which both functions are defined.
3) The domain excludes x = 2 because v(x) is not defined for x = 2.
4) And the domain must also exclude v(x) = 0 because u is not defined for v(x) = 0.
5) So, in conclusion, the domain is all the real values except x = 2 and the x for which v(x) = 0.
Therefore the resctrictions are x ≠ 2 and v(x) ≠ 0
Justification:
1) the function (u ° v) (x) is u [ v(x) ], this is, you have to apply first the function v(x) whose argument is (x), and later the function u (v(x) ) whose argument is v(x).
2) So, the domain of the composed function (u ° v) (x) has to take into account the values for which both functions are defined.
3) The domain excludes x = 2 because v(x) is not defined for x = 2.
4) And the domain must also exclude v(x) = 0 because u is not defined for v(x) = 0.
5) So, in conclusion, the domain is all the real values except x = 2 and the x for which v(x) = 0.
Therefore the resctrictions are x ≠ 2 and v(x) ≠ 0
Answer:
C: x Not-equals 2 and x cannot be any value for which v(x) Equals 0
Step-by-step explanation:
took the unit rev test :>