The percentage of sugar in the syrup is 16.66...%
Explanation
The amount of water in the syrup is 10 kg. and the amount of sugar is 2 kg.
So, the total amount of the syrup [tex] =(10+2) kg = 12 kg [/tex]
Percentage of sugar = [tex] \frac{(Amt. of sugar) }{(Amt. of syrup)} * 100 [/tex]%
[tex] \frac{2 kg}{12 kg} * 100 [/tex]% = [tex] \frac{50}{3} = 16.666... [/tex]%
So, the percentage of sugar in the syrup is 16.66...%
The percentage of sugar in the syrup made of 10 kg of water and 2 kg of sugar is 16.67% and this can be determined by using the unitary method.
Given :
The syrup is made of 10 kg of water and 2 kg of sugar.
The following steps can be used to determine the percentage of sugar in the syrup:
Step 1 - Unitary method can be used in order to determine the percentage of sugar in the syrup.
Step 2 - Determine the total weight of syrup that is the sum of the weight of water and the weight of sugar.
= 10 + 2
= 12 Kg
Step 3 - The total weight of syrup is 12Kg which is 100% so the weight percentage of sugar in the syrup is:
[tex]=\dfrac{2}{12}\times 100[/tex]
Multiply 2 by 100 in the above expression.
[tex]=\dfrac{200}{12}[/tex]
Divide 200 by 12 in the above expression.
= 16.67%
So, the percentage of sugar in the syrup made of 10 kg of water and 2 kg of sugar is 16.67%.
For more information, refer to the link given below:
https://brainly.com/question/16807456
