Question

What is the electric potential vtot at the center of the square? make the usual assumption that the potential tends to zero far away from a charge. express your answer in terms of q, d, and appropriate constants?

Answer 1

Answer:

$\frac{k10q}{\sqrt{2}d }$

Explanation:

Answer 2

The electric potential at the center of a square due to a charge at the corner of the square is $\frac{KQ}{2\sqrt{d} }$.

Distance at midpoint of a square

The distance at the midpoint of a square is obtained by diving the diagonal length by 2.

The diagonal length of a square is calculated as

$R^2 = d^2 + d^2\\\\R^2 = 2d^2\\\\R = \sqrt{2d^2} \\\\R = d \sqrt{2}$

Midpoint distance

$x = \frac{R}{2} = \frac{d\sqrt{2} }{2}$

The electric potential at the center of a square due to a charge at the corner of the square is calculated as follows;

$V = \frac{KQ}{R} = \frac{KQ}{2\sqrt{d} }$

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