Respuesta :
1. What is the skydiver's acceleration?
Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.
Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.
Answer:
[tex]a = g = 9.81 m/s^2[/tex]
Explanation:
As we know that there is no wind resistance on the skydiver
so when he jumps out of the helicopter then in that case the net force on the diver will be due to gravity only
so his equation for force is given by
[tex]F = mg[/tex]
now from the Newton's law of motion we will have
[tex]F_{net} = ma[/tex]
from the given options we will have
[tex]mg = ma[/tex]
so the acceleration is
[tex]a = g = 9.81 m/s^2[/tex]