Question

Determine the resistance of a 75-w lightbulb connected to its proper source voltage of 110 v.

Answer 1

We Know that:
P=V²R 
Hence; 
We have V=110 v and P=75 w

R=V²/P ⇒ 110²/75 
R=  12100/75
R= 161.33 Ω